# Advent calendar 2020

## 18 December

The expansion of \((x+y+z)^3\) is

$$x^3 + y^3 + z^3 + 3x^2y + 3x^2z + 3xy^2 + 3y^2z + 3xz^2 + 3yz^2 + 6xyz.$$
This has 10 terms.

Today's number is the number of terms in the expansion of \((x+y+z)^{26}\).

subscribe

The expansion of \((x+y+z)^3\) is

$$x^3 + y^3 + z^3 + 3x^2y + 3x^2z + 3xy^2 + 3y^2z + 3xz^2 + 3yz^2 + 6xyz.$$
This has 10 terms.

Today's number is the number of terms in the expansion of \((x+y+z)^{26}\).

Not Roman numerals

List of all puzzles