mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2019

10 December

For all values of \(x\), the function \(f(x)=ax+b\) satisfies
$$8x-8-x^2\leqslant f(x)\leqslant x^2.$$
What is \(f(65)\)?
Edit: The left-hand quadratic originally said \(8-8x-x^2\). This was a typo and has now been corrected.

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2020

Advent calendar 2019

Sunday Afternoon Maths LXVII

Coloured weights
Not Roman numerals

Advent calendar 2018


List of all puzzles

Tags

cube numbers complex numbers median squares numbers quadrilaterals digits christmas averages 2d shapes books dates area balancing circles chocolate sums advent multiplication parabolas remainders probabilty division irreducible numbers percentages sport multiples square numbers pascal's triangle algebra means coins lines clocks hexagons integration cryptic clues chess addition factorials 3d shapes partitions geometry bases differentiation crosswords graphs colouring elections probability factors indices ellipses trigonometry dice arrows doubling cryptic crossnumbers polygons palindromes time cards crossnumbers dodecagons coordinates mean perfect numbers integers star numbers logic combinatorics wordplay menace folding tube maps triangle numbers people maths taxicab geometry number odd numbers regular shapes calculus angles rugby sum to infinity functions rectangles routes prime numbers scales the only crossnumber unit fractions triangles shape chalkdust crossnumber square roots speed range tiling proportion digital clocks volume money perimeter spheres symmetry floors games sequences shapes products dominos quadratics fractions planes surds gerrymandering crossnumber ave grids

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2021