mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2018

18 December

There are 6 terms in the expansion of \((x+y+z)^2\):
$$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$$
Today's number is number of terms in the expansion of \((x+y+z)^{16}\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2019

Sunday Afternoon Maths LXVII

Coloured weights
Not Roman numerals

Advent calendar 2018

Sunday Afternoon Maths LXVI

Cryptic crossnumber #2

List of all puzzles

Tags

differentiation means rectangles cryptic crossnumbers cards graphs folding tube maps trigonometry polygons median rugby hexagons complex numbers circles spheres logic gerrymandering geometry menace dice surds area speed crossnumbers odd numbers sequences angles perimeter wordplay coordinates quadratics sport mean probabilty digits irreducible numbers dominos routes chess the only crossnumber ave 2d shapes factors dates volume fractions square roots multiples sum to infinity percentages money numbers colouring balancing taxicab geometry floors division probability elections triangles addition algebra remainders regular shapes advent parabolas ellipses people maths arrows prime numbers palindromes coins shape functions averages products square numbers indices crossnumber symmetry chocolate shapes star numbers sums bases crosswords pascal's triangle lines unit fractions books planes range multiplication cryptic clues partitions time chalkdust crossnumber christmas grids clocks 3d shapes factorials games cube numbers triangle numbers dodecagons integers proportion perfect numbers doubling tiling digital clocks integration squares scales calculus number

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2020