mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2018

18 December

There are 6 terms in the expansion of \((x+y+z)^2\):
$$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$$
Today's number is number of terms in the expansion of \((x+y+z)^{16}\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2025

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022


List of all puzzles

Tags

cryptic clues calculus area floors geometry squares mean differentiation xor star numbers matrices addition routes cube numbers medians crossnumbers symmetry irreducible numbers factorials geometric means crosswords perimeter percentages people maths digital products digital clocks books coins taxicab geometry cards fractions grids multiplication tournaments money proportion 3d shapes probabilty decahedra prime factors functions christmas averages folding tube maps regular shapes chalkdust crossnumber coordinates means time binary square roots bases polygons numbers prime numbers expansions digits shape consecutive integers angles tangents dice hexagons number geometric mean balancing rugby spheres even numbers sequences perfect numbers square numbers pascal's triangle determinants square grids division chess colouring advent albgebra integration median gerrymandering menace graphs volume clocks planes rectangles partitions range cryptic crossnumbers integers games lines surds doubling chocolate probability elections products dodecagons consecutive numbers complex numbers multiplaction squares sets ave logic axes triangle numbers circles combinatorics neighbours triangles quadrilaterals quadratics powers remainders speed tiling factors ellipses trigonometry scales parabolas 2d shapes polynomials sums pentagons unit fractions palindromes sum to infinity wordplay cubics indices algebra sport the only crossnumber lists dates arrows dominos shapes multiples odd numbers

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2026