mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2018

10 December

The equation \(x^2+1512x+414720=0\) has two integer solutions.
Today's number is the number of (positive or negative) integers \(b\) such that \(x^2+bx+414720=0\) has two integer solutions.

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2019

Sunday Afternoon Maths LXVII

Coloured weights
Not Roman numerals

Advent calendar 2018

Sunday Afternoon Maths LXVI

Cryptic crossnumber #2

List of all puzzles

Tags

quadratics doubling dodecagons cards range digital clocks square numbers area palindromes addition cryptic clues advent triangles 3d shapes games perimeter ellipses unit fractions median gerrymandering graphs functions probabilty fractions prime numbers factorials coins triangle numbers chalkdust crossnumber christmas the only crossnumber proportion square roots regular shapes mean number planes algebra crossnumbers odd numbers sequences menace elections 2d shapes trigonometry multiples speed lines means dice balancing taxicab geometry time numbers squares geometry angles probability bases differentiation arrows crossnumber hexagons cryptic crossnumbers routes sums people maths grids tiling sport sum to infinity colouring money indices dates symmetry rectangles shapes averages rugby cube numbers crosswords irreducible numbers scales dominos wordplay ave integration coordinates complex numbers shape division perfect numbers books parabolas spheres integers partitions calculus floors folding tube maps star numbers products factors pascal's triangle chocolate percentages chess clocks surds circles polygons multiplication digits logic remainders volume

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2020