mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2017

21 December

The factors of 6 (excluding 6 itself) are 1, 2 and 3. \(1+2+3=6\), so 6 is a perfect number.
Today's number is the only three digit perfect number.

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2025

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022


List of all puzzles

Tags

symmetry pentagons time surds functions integration multiplication binary square grids trigonometry determinants geometric means tangents planes chess hexagons taxicab geometry even numbers quadratics perfect numbers money geometric mean folding tube maps factorials cubics combinatorics colouring sum to infinity advent products logic factors albgebra division odd numbers wordplay 3d shapes angles the only crossnumber quadrilaterals axes sets squares prime factors expansions dice median polynomials balancing triangles geometry christmas parabolas neighbours rectangles digits number lines lists routes consecutive integers means crosswords bases square roots floors tiling polygons unit fractions books fractions ellipses shape sums crossnumbers cryptic crossnumbers dodecagons arrows graphs chalkdust crossnumber probabilty regular shapes powers addition spheres proportion ave elections rugby decahedra pascal's triangle differentiation coordinates games 2d shapes indices dates percentages multiples grids probability digital clocks cryptic clues menace complex numbers sport integers tournaments partitions digital products doubling mean star numbers cards gerrymandering palindromes dominos people maths triangle numbers numbers consecutive numbers multiplaction squares irreducible numbers algebra matrices range circles speed shapes square numbers remainders scales clocks sequences area medians chocolate perimeter coins calculus volume prime numbers cube numbers xor averages

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2026