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Advent calendar 2022
24 December
All 2022 advent puzzles
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The expression \((3x-1)^2\) can be expanded to give \(9x^2-6x+1\). The sum of the coefficients in this expansion is \(9-6+1=4\).
What is the sum of the coefficients in the expansion of \((3x-1)^7\)?
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The sum of the coefficients can be worked out by substituting \(x=1\) into the polynomial, so the sum of the coefficients is \((3-1)^7\), or
128
.
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functions
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tiling
decahedra
symmetry
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volume
folding tube maps
regular shapes
perfect numbers
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pascal's triangle
sport
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routes
polygons
range
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gerrymandering
games
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arrows
combinatorics
digital clocks
digital products
doubling
unit fractions
averages
elections
integration
sets
factors
numbers
dodecagons
2d shapes
palindromes
shape
complex numbers
sum to infinity
quadratics
ave
triangles
calculus
cards
partitions
planes
books
square roots
algebra
chalkdust crossnumber
binary
odd numbers
cryptic clues
median
wordplay
square numbers
angles
sequences
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coins
irreducible numbers
spheres
digits
crossnumber
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even numbers
consecutive integers
geometry
chocolate
integers
tangents
shapes
crosswords
money
coordinates
the only crossnumber
star numbers
balancing
perimeter
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mean
colouring
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