mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2022

24 December

The expression \((3x-1)^2\) can be expanded to give \(9x^2-6x+1\). The sum of the coefficients in this expansion is \(9-6+1=4\).
What is the sum of the coefficients in the expansion of \((3x-1)^7\)?

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2025

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022


List of all puzzles

Tags

axes matrices cryptic clues perimeter rugby angles decahedra medians addition games surds numbers calculus shapes powers cryptic crossnumbers polynomials xor consecutive numbers grids sets dodecagons cards ellipses symmetry regular shapes hexagons prime numbers percentages products perfect numbers irreducible numbers routes christmas gerrymandering area indices algebra time combinatorics star numbers parabolas shape chocolate albgebra sums trigonometry tiling palindromes determinants books coordinates floors digital clocks balancing expansions polygons 2d shapes neighbours digital products median ave square roots taxicab geometry geometric mean probabilty lines prime factors geometric means dates number graphs chess factors cube numbers advent partitions mean sport folding tube maps clocks multiples differentiation spheres logic unit fractions range people maths doubling binary wordplay integration probability digits the only crossnumber bases dominos quadrilaterals fractions volume integers factorials averages coins sequences lists circles menace scales multiplication sum to infinity triangle numbers colouring squares dice remainders proportion tournaments 3d shapes pentagons rectangles division tangents means complex numbers crosswords consecutive integers money quadratics cubics square grids pascal's triangle chalkdust crossnumber odd numbers crossnumbers square numbers speed multiplaction squares arrows geometry planes functions even numbers elections triangles

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2026