mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2022

24 December

The expression \((3x-1)^2\) can be expanded to give \(9x^2-6x+1\). The sum of the coefficients in this expansion is \(9-6+1=4\).
What is the sum of the coefficients in the expansion of \((3x-1)^7\)?

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2025

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022


List of all puzzles

Tags

geometry axes digital products rugby complex numbers bases tangents the only crossnumber functions lists balancing menace lines probability remainders integration digital clocks triangle numbers cube numbers grids ave squares coordinates neighbours rectangles multiplaction squares planes trigonometry volume area median square roots products number scales combinatorics doubling cryptic crossnumbers symmetry probabilty tiling pentagons unit fractions wordplay proportion chalkdust crossnumber xor medians range polynomials arrows dates differentiation dice gerrymandering multiplication tournaments surds pascal's triangle multiples digits dominos quadratics sum to infinity 2d shapes routes percentages triangles cryptic clues binary logic cards means sums addition colouring chess graphs matrices determinants shape polygons chocolate advent angles sport 3d shapes prime factors clocks elections geometric means powers square numbers expansions even numbers spheres factors decahedra money shapes square grids mean division palindromes factorials circles folding tube maps sets star numbers hexagons taxicab geometry christmas fractions books partitions games calculus odd numbers perfect numbers sequences time perimeter parabolas regular shapes irreducible numbers people maths coins indices consecutive integers speed floors dodecagons crossnumbers prime numbers quadrilaterals geometric mean averages crosswords consecutive numbers algebra ellipses albgebra numbers cubics integers

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2026