mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2022

24 December

The expression \((3x-1)^2\) can be expanded to give \(9x^2-6x+1\). The sum of the coefficients in this expansion is \(9-6+1=4\).
What is the sum of the coefficients in the expansion of \((3x-1)^7\)?

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2025

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022


List of all puzzles

Tags

balancing 2d shapes calculus probabilty cards consecutive numbers division odd numbers angles books coordinates triangles square grids chess pascal's triangle lines square numbers symmetry taxicab geometry volume shapes polynomials cube numbers factors gerrymandering dates graphs chalkdust crossnumber unit fractions sums digital clocks numbers games chocolate dodecagons albgebra colouring money squares bases trigonometry neighbours digits factorials combinatorics crossnumbers dice elections differentiation number tournaments dominos consecutive integers sets proportion routes pentagons axes products expansions mean square roots sum to infinity range prime numbers spheres cubics logic palindromes geometry functions digital products tangents fractions time xor medians ellipses perimeter matrices means powers advent multiplication indices cryptic clues shape clocks people maths scales christmas perfect numbers irreducible numbers percentages cryptic crossnumbers complex numbers quadrilaterals partitions sport remainders median hexagons rugby quadratics wordplay probability polygons grids arrows circles geometric means coins doubling area speed planes 3d shapes averages determinants decahedra folding tube maps tiling even numbers addition ave parabolas rectangles triangle numbers regular shapes multiples surds algebra the only crossnumber binary sequences crosswords geometric mean star numbers integers prime factors floors menace multiplaction squares integration lists

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2026