mscroggs.co.uk
mscroggs.co.uk

subscribe

Puzzles

Archive

Show me a random puzzle
 Most recent collections 

Tags

unit fractions addition quadratics perimeter digits time circles sport 2d shapes spheres percentages floors grids multiples 3d shapes division square roots algebra chocolate doubling dice taxicab geometry bases chalkdust crossnumber hexagons factors rectangles star numbers prime numbers balancing calculus chess games integers cards triangles averages dates squares numbers books ellipses palindromes colouring arrows logic parabolas cryptic crossnumbers area polygons shape advent irreducible numbers ave cryptic clues coordinates sums cube numbers symmetry sum to infinity triangle numbers scales coins christmas rugby trigonometry geometry partitions fractions graphs differentiation folding tube maps people maths lines multiplication functions square numbers pascal's triangle integration sequences odd numbers surds speed dodecagons shapes number wordplay proportion factorials probabilty routes money crossnumbers indices mean probability remainders clocks angles volume crosswords perfect numbers regular shapes complex numbers menace planes means

Archive

Show me a random puzzle
▼ show ▼

Backwards fours

If A, B, C, D and E are all unique digits, what values would work with the following equation?
$$ABCCDE\times 4 = EDCCBA$$

Show answer

If you enjoyed this puzzle, check out Sunday Afternoon Maths LXIV,
puzzles about multiplication, or a random puzzle.
© Matthew Scroggs 2019