mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2019

7 December

The sum of the coefficients in the expansion of \((x+1)^5\) is 32. Today's number is the sum of the coefficients in the expansion of \((2x+1)^5\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2023

Advent calendar 2022

Advent calendar 2021

Advent calendar 2020


List of all puzzles

Tags

median indices dodecagons rectangles sport ave bases routes rugby calculus differentiation cards range folding tube maps quadratics arrows digital clocks averages geometric means algebra triangle numbers coins albgebra speed colouring balancing remainders clocks circles expansions taxicab geometry number grids doubling sums chocolate axes unit fractions palindromes products sum to infinity chalkdust crossnumber digital products geometry gerrymandering shapes integration hexagons consecutive integers multiples parabolas crossnumber numbers functions polynomials sets division mean proportion multiplication matrices advent books addition shape lines tangents squares binary floors pascal's triangle trigonometry graphs means factorials time surds polygons partitions square roots logic crosswords dice probabilty decahedra people maths elections odd numbers crossnumbers regular shapes factors volume ellipses games scales area digits menace probability determinants prime numbers cryptic crossnumbers tiling the only crossnumber cubics cryptic clues 3d shapes christmas dates quadrilaterals combinatorics 2d shapes dominos fractions perimeter spheres chess complex numbers triangles sequences square numbers tournaments cube numbers integers star numbers angles consecutive numbers symmetry planes money even numbers geometric mean coordinates perfect numbers percentages irreducible numbers wordplay pentagons

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2024